5^2-(3x+28)=3(x+1)

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Solution for 5^2-(3x+28)=3(x+1) equation: 



5^2-(3x+28)=3(x+1)

We move all terms to the left:

5^2-(3x+28)-(3(x+1))=0

We add all the numbers together, and all the variables

-(3x+28)-(3(x+1))+25=0

We get rid of parentheses

-3x-(3(x+1))-28+25=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

-3x-(3x+3)-3=0

We get rid of parentheses

-3x-3x-3-3=0

We add all the numbers together, and all the variables

-6x-6=0

We move all terms containing x to the left, all other terms to the right

-6x=6

x=6/-6

x=-1

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